-16t^2+44t-10=0

Solution for -16t^2+44t-10=0 equation:

-16t^2+44t-10=0

a = -16; b = 44; c = -10;
Δ = b2-4ac
Δ = 442-4·(-16)·(-10)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-36}{2*-16}=\frac{-80}{-32}
=2+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+36}{2*-16}=\frac{-8}{-32}
=1/4
$